Question

The number of moles of oxalic acid present in 400 ml of 0.025M of oxalic acid solution

Answer 1

Correct option is

C

1.575 g

n. factor for H2C2O4 =2

Equivalent weight =2M

Normality = equivalentweight×volume(inmL)weight×1000

0.1=(2126)×250weight×1000

Therefore, weight = 1.575g

Answer 2

Answer:

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