The number of moles of oxygen in 1 L of air containing 21% oxygen by volume, in standard conditions, is:
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Answered by
1
Answer:
0.0094
Explanation:
At standard conditions, 1 liter of air at 21% oxygen possesses 0.21 L of oxygen. Since at STP 1 mole of gas occupies 22.4 L, simply divide 0.21/22.4, to arrive at 0.0094 moles of oxygen.
Answered by
0
Answer:
0.009
Explanation:
0.009
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