The number of moles of potassium chlorate required to produce 67.2 ml of oxygen gas
at STP is
X10' moles.
Answers
Answered by
0
Answer:
number of moles of potassium chlorate required to produce 67.2 ml of oxygen gas
Explanation:
number of moles of potassium chlorate required to produce 67.2 ml of oxygen gas pas
Similar questions