Question

The number of moles of SO2 that can be oxidised in maximum by one mole of each KMno4,K2Cr2O7 in acidic medium respectively


why prince​

Answer 1

Explanation:

The number of moles of SO2 that can be oxidized in maximum by one mole of each KMnO4 , K2Cr2O7 in acidic medium respectively are?

[MnO4- + 8H+ + 5e → Mn2+ + 4 H2O] ×2 (reduction half reaction)

[SO2 + 2H2O → SO4^2- + 4 H+ + 2e] × 5 (oxidation half reaction)

Cr2O7^2- + 14 H+ + 6e → 2Cr3+ + 7H2O (reduction half reaction)

[SO2 + 2H2O → SO4^2- + 4 H+ + 2e] × 3 (oxidation half reaction)

From the above half reactions, we can write, 2 moles of KMnO4 oxidize 5 moles of SO2.

So, 1 mole of KMnO4 oxidizes 2.5 moles of SO2.

Similarly, 1 mole of K2Cr2O7 oxidizes 3 moles of SO2.

Hope this helps.

Answer 2

(So, 1 mole of KMnO4 oxidizes 2.5 moles of SO2. Similarly, 1 mole of K2Cr2O7 oxidizes 3 moles of SO2. Hope this helps.

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