Question

The number of moles of solute
present in 2 dm3 of 0.5 M solution is​

Answer 1

Answer:

it is 0.25 mole

Explanation:

M=n × 1/V in L

0.5= n× 1/0.5 bcz 1 dm3 = 1 ltr

so, answer is 0.25 moles

pls verify ones...