Question

the number of moles of sucrose present in 171 gmsof sucrose (c12,h22o11j​

Answer 1

Answer:

1/2 mole

Explanation:

C12H22O11

molecular mass= 12×12+22×1+16×11 g

M. mass=342 g

342gof sucrose contain 1 mole

so 171 g will contain = 171 ×1/342

moles = 1/2 .

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