Question

The number of moles of water present in 100 g of water of 90% purity is​

Answer 1

Answer:

no of moles = 90/18= 5 moles.....

Answer 2

Purity = Mass of Pure substance/Total mass *100

=Mass of Pure Substance= Purity*Total mass/100

=90 * 100 /100

= 90 g of Pure water is there

No. of moles = Amount of water/molecular mass

Molecular Mass of water = 18g

=90/18

= 5 moles are present