Question

the number of moles present in 316 gm of potassium permanent is​

Answer 1

Answer:

Correct option is

C

0.25 mole

Molecular weight of KMnO

4

is [39+55+(16×4)], which is equal to 158grams

158grams of KMnO

4

contains 55grams of Potassium. (atomic weight of Potassium is 55grams)

40grams of KMnO

4

contains

158

55

∗40, which is almost equal to 14grams of Potassium

Now,

55grams of Potassium equals to 1mole of Potassium

1gram of Potassium equals to

55

1

mole of Potassium

Thus, 14grams of Potassium equals to

55

1

∗14mole of Potassium, which is almost equal to 0.25mole of Potassium

Option C is the correct answer.