the number of moles present in 316 gm of potassium permanent is
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Answer:
Correct option is
C
0.25 mole
Molecular weight of KMnO
4
is [39+55+(16×4)], which is equal to 158grams
158grams of KMnO
4
contains 55grams of Potassium. (atomic weight of Potassium is 55grams)
40grams of KMnO
4
contains
158
55
∗40, which is almost equal to 14grams of Potassium
Now,
55grams of Potassium equals to 1mole of Potassium
1gram of Potassium equals to
55
1
mole of Potassium
Thus, 14grams of Potassium equals to
55
1
∗14mole of Potassium, which is almost equal to 0.25mole of Potassium
Option C is the correct answer.
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