Question

The number of moles present in 4.9g of sulphuric acid is

Answer 1

Explanation:

$Molecular \:weight \:of\: H_2SO_4 -</p><p>\\ \\</p><p>1×2 + 32 + 16×4</p><p>\\ \\</p><p>2+32+64</p><p>\\ \\</p><p>= 98$

$mass = mole(n) \times gram \: molecular \: mass \\ \\ mole(n) = \frac{mass}{gram \: molecular \: mass} \\ \\ = \frac{4.9}{98} \\ \\ = \frac{1}{20} \\ \\ = 0.05 \: mole$

Answer 2

Answer:

Explanation:

Amount of mass present in one mole of sulphuric acid =98

Therefore no. Of moles present in 4.9 g =4.9/98

= 0.05 moles

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