the number of moles present in 4.9g of sulphuric acid is.?
Answers
Answered by
41
Given ⇒
Mass of the Sulphuric Acid = 4.9 g.
Molar mass of the sulphuric acid = 98 g/mole.
Now, Using the Formula,
No. of moles of the Sulphuric Acid = Mass/Molar mass.
∴ No. of moles of the sulphuric acid = 4.9/98
∴ No. of moles of the sulphuric acid = 0.05 moles.
Hence, the number of moles of the Sulphuric Acid is 0.05 moles.
Hope it helps.
Mass of the Sulphuric Acid = 4.9 g.
Molar mass of the sulphuric acid = 98 g/mole.
Now, Using the Formula,
No. of moles of the Sulphuric Acid = Mass/Molar mass.
∴ No. of moles of the sulphuric acid = 4.9/98
∴ No. of moles of the sulphuric acid = 0.05 moles.
Hence, the number of moles of the Sulphuric Acid is 0.05 moles.
Hope it helps.
Answered by
5
Answer:
answer =0.05
Explanation:
Mass of Sulphuric acid =4.9 g
Molar mass of the Sulphuric acid =98g/moles
therfore, No. of moles of the sulphuric Acid =Mass/Moles mass
No. of moles of the sulphuric acid=4.9/98
=0.05 moles
Similar questions