Question

the number of moles present in 4.9g of sulphuric acid is?​

Answer 1

Given ⇒
Mass of the Sulphuric Acid = 4.9 g.
Molar mass of the sulphuric acid = 98 g/mole.

Now, Using the Formula,
No. of moles of the Sulphuric Acid = Mass/Molar mass.
∴ No. of moles of the sulphuric acid = 4.9/98
∴ No. of moles of the sulphuric acid = 0.05 moles.

Answer 2

Explanation:

molar mass of sulphuric acid

is H2So4 = 2+ 32+64 = 98g

now in 4.9g of sulphuric acid

no. of moles present is = 4.9/98

= 0.1/2

=0.05 moles