Question

the number of moles present in 48 lit of O2 at STP is​

Answer 1

Answer:

1.5 moles

Explanation:

Moles=  

molecular weight

Weight

​

 

Molecular weight of O  

2

​

=32g/mol

Moles=  

32

48

​

 =1.5 moles

Answer 2

Given,

The volume of O₂ gas at STP = 48L

To find,

The number of moles of O₂ at given conditions

Solution,

At STP, the pressure is 1 atm and the temperature is 273K. The proportionality constant, R, is equal to 0.0821 $\frac{L * atm}{mol * K}$

Now, using the ideal gas law equation,

P × V = n × R × T

where,

• P = Pressure (atm)
• V = Volume (litre)
• n = Number of moles
• R = Universal gas constant ($\frac{L * atm}{mol * K}$)
• T = Temperature (Kelvin)

Further, rearranging the ideal gas equation to get the number of moles

⇒ n = $\frac{PV}{RT}$

Inserting values into the equation,

⇒ n = $\frac{(1)(48) }{(0.0821)(273)}$

⇒ n = 2.14 moles

Hence, 48 litres of O₂ at STP = 2.14 moles.