The number of multiples lie between n and n² which are divisible by n is
(a) 2n²
(b) 2n + 1
(c) 2n – 1
(d) n²
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Step-by-step explanation:
Multiples of n from 1 to n² are n × 1, n × 2, n × 3, …, m× n
∴ There are n numbers
Thus, the number of mutiples of n which lie between n and n² is (n – 2) leaving first and last in the given list: Total numbers are (n – 2).
hope it's helpful to you..(•‿•)
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