The number of multiples of 4 between 10 and 250 is
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60 Multiples
Answer: 60 Multiples of 4 lies between 10 and 250.
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multiples of 4 between 10 and 250 are: 12, 16, 20, 24,....248
multiples of 4 between 10 and 250 are: 12, 16, 20, 24,....248Now, this forms an Arithmetic Progression
We need to find the number of terms (n) which ends at 248.
We need to find the number of terms (n) which ends at 248.Using formula of Arithmetic Progression:
We need to find the number of terms (n) which ends at 248.Using formula of Arithmetic Progression:an = a + (n - 1)(d)
We need to find the number of terms (n) which ends at 248.Using formula of Arithmetic Progression:an = a + (n - 1)(d)248 = 12 + (n - 1)(4)
We need to find the number of terms (n) which ends at 248.Using formula of Arithmetic Progression:an = a + (n - 1)(d)248 = 12 + (n - 1)(4)248 - 12 = 4 (n - 1)
We need to find the number of terms (n) which ends at 248.Using formula of Arithmetic Progression:an = a + (n - 1)(d)248 = 12 + (n - 1)(4)248 - 12 = 4 (n - 1)236 = 4 (n - 1)
We need to find the number of terms (n) which ends at 248.Using formula of Arithmetic Progression:an = a + (n - 1)(d)248 = 12 + (n - 1)(4)248 - 12 = 4 (n - 1)236 = 4 (n - 1)59 = n - 1
We need to find the number of terms (n) which ends at 248.Using formula of Arithmetic Progression:an = a + (n - 1)(d)248 = 12 + (n - 1)(4)248 - 12 = 4 (n - 1)236 = 4 (n - 1)59 = n - 1n = 60
We need to find the number of terms (n) which ends at 248.Using formula of Arithmetic Progression:an = a + (n - 1)(d)248 = 12 + (n - 1)(4)248 - 12 = 4 (n - 1)236 = 4 (n - 1)59 = n - 1n = 60there are 60 terms, which means there are 60 multiples of 4 between 10 and 250.
We need to find the number of terms (n) which ends at 248.Using formula of Arithmetic Progression:an = a + (n - 1)(d)248 = 12 + (n - 1)(4)248 - 12 = 4 (n - 1)236 = 4 (n - 1)59 = n - 1n = 60there are 60 terms, which means there are 60 multiples of 4 between 10 and 250.Thus, 60 multiples of 4 lie between 10 and 250.