The number of multiples of
that divides
is
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LHS :
cos2xcos2x−cos3xcos29x
=21[2cos2xcos2x−2cos3xcos29x]
=21[cos[(2x+2x)+cos(2x−2x)]−[cos(3x+29x)+cos(29x−3x)]]
=21[cos25x+cos23x−cos215x−cos23x]
=21[cos25x−cos215x
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