Question

the number of nitrogen atoms present in 6.0g of
urea

Answer 1

Explanation:

(0.6g urea x 8 atoms per molecule of urea x Avagadro Number)/(weight of i mole of urea)

0.6 x 8 x 6.023 x 10.23)/ 60.056

4.8139 x 10(22)

(pardon me, I may have made a mistake, wait until someone else answers