The number of nuclei in 10 grams of 60Co27 is?
Answers
Answered by
0
Explanation:
Given,
T
1/2
=5.3year
T
1/2
=5.3×365×24×60×60=1.67×10
8
sec
dt
dN
=8.0mCI
dt
dN
=8×10
−3
×3.7×10
10
=29.6×10
7
decay/sec
Half- life, T
1/2
=
λ
0.693
λ=
T
1/2
0.693
=
1.67×10
8
0.693
λ=0.414×10
−8
s
−1
Radioactive rate,
dt
dN
=λN
N=
λ
1
.
dt
dN
N=
0.414×10
−8
29.6×10
7
=7.15×10
16
atom
For
27
60
Co,
mass of 6.022×10
23
atom=60g
mass of one atom =
6.022×10
23
60
g
mass of one atom 7.15×10
16
atom≡
6.022×10
23
60×7.15×10
16
g=7.123×10
−6
g
Hence, the amount of
27
60
Co is 7.123×10
−6
g.
Answer By : jeevanantham
Mark me as brainlist
Similar questions