the number of numbers between 74 and 25556 divisible by 5
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first number divisible by 5=75
and the last number divisible by 5=25555
we know
an=a+(n-1)d
25555=75+(n-1)5
25555-75=(n-1)5
25480=(n-1)5
5096=n-1
n=5096+1
=5097
therefore there are 5098 numbers
and the last number divisible by 5=25555
we know
an=a+(n-1)d
25555=75+(n-1)5
25555-75=(n-1)5
25480=(n-1)5
5096=n-1
n=5096+1
=5097
therefore there are 5098 numbers
Anonymous:
oh leave it hogaya hoga
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