Question

The number of numbers lying between 10 to 1000 can be formed with the digits 2,3,4,0,8,9, is

Answer 1

All remaining digits will have6 choices each. Number lying between 100 and 1000 are 3-digit numbers . 3-digit numbers that can be formed using 0,2,3,4,5,6 = 5*6*6.
So, the total number of different numbers that can be formed using {0,2,3,4,5,6} = 5*6*6.

Answer 2

Answer:

The answer will be 125.

Step-by-step explanation:

TOTAL OF 2DIGIT NUMBERS

We can choose the tens digit any of 5 ways (0 cannot be chosen)

We can then choose the units digit any of 5 ways, because 0 can be chosen.

That's 5 x 5 or 25 two digit numbers

THREE DIGIT NUMBERS:

We can choose the hundreds digit any of 5 ways (0 cannot be chosen)

We can then choose the tens digit any of 5 ways, because 0 can be chosen.

We can then choose the units digit any of the 4 remaining ways.

That's 5 x 5 x 4 = 100 three-digit numbers

So, total: 25+100 = 125 .