The number of one-one functions that can be defined from A =(4,8,12,16) to B is 5040, the n(B)
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GIVEN n(A)=4 and no:of one-one function is 5040
so we should find n(B)=
First do n!/(n-m)!=5040
next substitute n!/(n-4)!=5040
= n(n-1)(n-2)(n-3)(n-4)!/(n-4)!=5040
=n(n-1)(n-2)(n-3)=5040
next substitute the big digit in the given options and substitute then you will get LHS=RHS
Other wise it is descriptive take the digits after 5 as the question indicating the bigger value 5040
so then 10(10-1)(10-2)(10-3)=5040
10*9*8*7=5040
So LHS=RHS
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