Question

The number of oxygen atoms in 20 g sulphur trioxide (SO3) is the same as those present in 'X' gram of ozone. The atomic masses of S and O are 32 u and 16 u respectively.
Find the value of 'X'.
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Answer 1

Answer:36g.

Explanation:

Mol. Wt of so3= 80

Moles of so3=20/80= 1/4 moles.

1 mole so3 has 3 moles of oxygen.

Thus 1/4 moles will have 3/4 moles of oxygen.

Xg of o3 have same no. Of oxygen atoms means have same moles of oxygen as so3.

1 mole of o3 have 3 moles of oxygen.

Thus X/48 moles will have 3/4 moles of oxygen ( unitary method) by solving we will get x as 36g.

( mol. Wt of o3 is 48).

Thank you.

Answer 2

Answer:

The number of oxygen atoms in 20 grams of sulphur trioxide is same as that present in X grams of ozone . The atomic mass of sulphur and oxygen are 32u and 16u respectively . find the value of X. 4.515 x 1023 atoms make (48 / 6.02 x 1023) x 4.515 x 1023 = 36 g ozone.