Question

The number of oxygen atoms in 300g of caco3 is?

Answer 1

Answer:

The number of oxygen atoms is 5.4198×10²⁴

Explanation:

1 mole of CaCO3 = 40×1+12×1+16×3

= 100g

mass of oxygen in CaCO3 = 3×16 = 48 g

so 100 g of CaCO3 has 48 g oxygen

1g will have = 48÷100

now 300 g will have = 300×48÷100 = 144 g of oxygen

1 mole of oxygen = 16 g

so 16 g will have 6.022×10²³ molecule

now 1 g will have 6.022×10²³÷16

Again 144 g will have = 144×6.022×10²³÷16

= 9×6.022×10²³ = 54.198×10²³

= 5.4198×10²⁴ atoms of oxygen

So in 300 g of CaCO3 there will be 5.4186 ×10 ²⁴ atoms of oxygen