Question

the number of oxygen atoms in 6.4g of SO2 is:​

Answer 1

Answer:

1.2*10^23 atoms

Explanation:

1 mole of O2 contains 6.022*10^23 atoms of O2

molecular mass of Oxygen= 16*2=32 amu

given mass/ molar mass= number of moles

6.4/32=0.2 moles

Number of O2 atoms = avagadro no. * no of moles

=6.022*10^23 *0.2

=1.2044* 10^23 atoms

=1.2*10^23 atoms

Answer 2

Given:

6.4 grams of sulfur dioxide.

To find:

The number of oxygen atoms.

Solution:

The chemical formula of sulfur dioxide is $SO_2$.

The atomic weight of Sulfur is 32 grams and oxygen is 16 grams.

Hence the molecular weight of sulfur dioxide is 32+16×2=64 grams.

64 grams of sulfur dioxide contains $2×6.022×10^{23}$ number of oxygen atoms.

6.4 grams of sulfur dioxide contains $12.044×10^{23}×6.4/64=12.044×10^{22}$ number of oxygen atoms.

6.4 grams of sulfur dioxide contains $1.2×10^{23}$ number of oxygen atoms.

Hence the correct option is d.