Question

the number of oxygen atoms present in 25.6g of sucrose (c12H22o11) which has a molar mas of 342.3g is .

a:) 22 ×10^23

B:) 9.91 ×10^23

c:) 11 × 10 ^23

d:) 44 × 10^23

Answer 1

answer :-

moles of c12H22011 =

=> 25.6 / 342 .3 = 0.0747

number of H atoms


= 0.0747 × 22 × 6.023 × 23

= 9.91 × 10 ^23


options ( b)


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Answer 2

Answer-:

Moles of c12H22011

=> 25. 6/342.3=0.0747

Number of H atoms

=> 0.0747×22×6.023×23

=> 9.91×10^23

=> (B) is correct

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