Question

•
The number of oxygen atoms present in 50g of calcium carbonate is
1) 6.023 x 1023 ) 30.1 x 1023 3) 9.035 x 1023​

Answer 1

Answer:

the answer is 30.1*1023

Answer 2

Answer:9.035×10^23

Explanation:mass of caco3 is 100g

From Avogadro's rule we can write the no.of atoms in Caco3

For 100g of Caco3 - 3×6.023×10^23

For 50 g of Caco3 - ?

By cross multiplication here we get

the no of oxygen atoms present in 50g of Caco3 i.e. 9.035×10^23