Question

The number of oxygen molecules in a cylinder
of volume 1 mº at a temperature of 27°C and
pressure 13.8 Pa is :
(Boltzmaan's constant k = 1.38 x 10-23 JK-1)
(1) 6.23 x 1026 (2) 0.33 x 1028
(3) 3.3 x 1021
(4) None of these​

Answer 1

Answer:

3

Explanation:

Use the ideal gas law.

Answer 2

Correct option is (3) .

Given :

Volume , $V=1\ m^3$ .

Temperature , T = 27 + 273 K = 300 K .

Pressure , P = 13.8 Pa .

Also , $K_b=1.38\times 10^{-23}\ JK^{-1}$ .

We know , $R=K_bN_a$

We also , know :

PV=nRT

Also , $n=\dfrac{x}{N_a}$

Putting all we get ,

$PV=\dfrac{x\times (K_bN_a)\times T}{N_a}$

Putting all values we get :

x = $3.3\times 10^{21}$

Hence , this is the required solution .

Learn More :

Thermodynamics

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