The number of oxygen molecules in a cylinder of volume 1m3 at temperature 327C and pressure 27.6 Pascal is= ?
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Answers
The number of oxygen molecules in a cylinder of volume 1m3 at temperature 327C and pressure 27.6 Pascal is= ?
Given,
Pressure, P=13.8Pa
Temperature, T=(27+273.15)K
Volume V=1 m 3 Boltzman constant k B =1.38×10−23 JK −1R
universa =N A K B
=(6.023×10 23 )×(1.38×10 −23 )=8.314 J/mol
Apply Ideal gas equationPV=nRT
n= RTPV
= 8.314(27+273.15)13.8×1
=5.53×10 −3 mol
x=n×N A
=(5.53×10 −3 )×(6.023×10 +23 )=3.33×10 21
molecules
Number of molecules is 3.33×10 21
Given:-
- Volume = V = 1 m³
- Temperature = T = 327 °C
- Pressure = 27.6 Pa
━━━━━━━━━━━━━━━
Need to find:-
- Number of molecules of Oxygen = ?
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Solution:-
→ Temperature
= 327°C
= 327 + 273 K
= 600K
We know from IDEAL GAS EQUATION that:
PV = nRT
Where,
- P = Pressure
- V = Volume
- n = Number of moles
- R = Gas Constant = 25/3
- T = Temperature (always in Kelvin)
Substitute the values:-
→ 27.6 × 1 = n × 25/3 × 600
→ 27.6 = n × 25 × 200
→ n = 27.6 ÷ (25 × 200) moles
→ n = 27.6 ÷ 5000 moles
→ n = 5.52 × 10⁻³ moles
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Number of Molecules:
= Number of moles × Avogardo's Number
= 5.52 × 10⁻³ × 6.022 × 10²³
= 33.24 × 10²⁰ (ans)
⋆ There will be 33.24 × 10²⁰ molecules of Oxygen.