Question

The number of permutations of 4 letters from the letters of the word Kolkata is???

Answer 1

The number of permutations =P(7,4)/2!*2!
=7*6*5*4/2*2=210
Out of 7 letters k repeated 2 times and a repeated 2 times.

Answer 2

Answer:

210.

Step-by-step explanation:

Required formula: P(n,r) = n! / (n-r)!

According to the question, the word 'KOLKATA' has 7 letters among which there are 2 'K's and 2 'A's.

Thus the permutaion of any 4 letters among these 7 can be expressed as;

P(7,4) = 7! / [(7-4)! X (2! X 2!)] [As, n= 7 and r = 4; 2 '2!' are for the 2 letters with repeatations]

or, P(7,4) = (7 X 6 X 5 X 4) / (2 X 2)

or, P(7,4) = 210