Chemistry, asked by kaustubhadagade8895, 12 hours ago

The number of phases in following equilibrium is
Na2S04.10H2O (S) = Na2S04 (S) + 10 H2O (9)

A 0

B 2

С 1

D 3

Answers

Answered by roshanjalan01jmp
0

Answer:

b

not sure about this

it is my rough idea

Similar questions