Question

the number of Pi electrons present in 2.6 gram of ethyne is

Answer 1

Answer:2.40* 10^23

Explanation: ### no. Of π bonds in ethyne = 2

### no. Of electron involved in 2π bonds = 4 ( 2 electrons each )

###no. Of moles of ethyne = given mass / molecular mass = 2.6/26 = 0.1

### now no. Electrons in 0.1 mole ethyne = Na * moles * no. Of electron

~~ = 6. 022 * 0.1 * 4 = 2.40 * 10^23

Answer 2

Answer:

Number of π electrons $=6.022*10^{22}$

Explanation:

We know that the number of π bonds in ethyne $= 2$

Number of electron involved in $2$ π bonds $= 4$ ( $2$ electrons each )

Number of moles of ethyne : $\frac{given mass}{molecular mass}$

$\frac{2.6}{26}= 0.1$

Now, number of electrons in $0.1$ mole of ethyne $= N_A$ * moles * number of electrons :

$= 6. 022 * 10^{23}*0.1 * 4$

$=2.4*10^{23}$

First, we have to find the number of moles :

Molar mass of ethyne $=26$

Given weight $=2.6$

Number of moles $=\frac{2,6}{26} =0.1 mol$

Hence, the number of π electrons is : $0.1*6.022*10^{23}$

$=6.022*10^{22}$