Question

The number of points at which the given polynomial  x x x   1 3   intersects with ‘x’ axis is :

(A) 3 (B) 2 (C) 1 (D) 4
plz explain the procedure also​

Answer 1

SOLUTION

TO CHOOSE THE CORRECT OPTION

The number of points at which the given polynomial

$\sf{(x + 1)(x + 3)x}$

intersects with ‘x’ axis is :

(A) 3 (B) 2 (C) 1 (D) 4

CONCEPT TO BE IMPLEMENTED

• The zero of a polynomial is the x coordinate of the point where it cuts X axis

• Total number of zeros of the polynomial is the number of time the graph of the polynomial cuts X axis

EVALUATION

Let p(x) be the polynomial

$\sf{p(x) = (x + 1)(x + 3)x}$

For Zero of the polynomial p(x) we have

$\sf{ p(x) = 0\: }$

$\implies \sf{(x + 1)(x + 3)x = 0 \: }$

$\implies \sf{x = - 1, - 3, 0 \: }$

So the Zeros of the polynomial p(x) are - 1 , - 3 , 0

Hence the the polynomial cut x axis three times and the points are ( - 1, 0), ( - 3,0), ( 0,0)

VERIFICATION

In the attachment from the graph of the polynomial we can check that the polynomial cut x axis three times and the points are

A( - 1, 0), B( - 3,0) , C( 0,0)

FINAL ANSWER

The number of points at which the given polynomial $\sf{(x + 1)(x + 3)x}$

intersects with X axis is :

(A) 3

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Answer 2

Step-by-step explanation:

TO CHOOSE THE CORRECT OPTION

The number of points at which the given polynomial

\sf{(x + 1)(x + 3)x}(x+1)(x+3)x

intersects with ‘x’ axis is :

(A) 3 (B) 2 (C) 1 (D) 4

CONCEPT TO BE IMPLEMENTED

The zero of a polynomial is the x coordinate of the point where it cuts X axis

Total number of zeros of the polynomial is the number of time the graph of the polynomial cuts X axis

EVALUATION

Let p(x) be the polynomial

\sf{p(x) = (x + 1)(x + 3)x}p(x)=(x+1)(x+3)x

For Zero of the polynomial p(x) we have

\sf{ p(x) = 0\: }p(x)=0

\implies \sf{(x + 1)(x + 3)x = 0 \: }⟹(x+1)(x+3)x=0

\implies \sf{x = - 1, - 3, 0 \: }⟹x=−1,−3,0

So the Zeros of the polynomial p(x) are - 1 , - 3 , 0

Hence the the polynomial cut x axis three times and the points are ( - 1, 0), ( - 3,0), ( 0,0)

VERIFICATION

In the attachment from the graph of the polynomial we can check that the polynomial cut x axis three times and the points are

A( - 1, 0), B( - 3,0) , C( 0,0)

FINAL ANSWER

The number of points at which the given polynomial \sf{(x + 1)(x + 3)x}(x+1)(x+3)x

intersects with X axis is :

(A) 3

━━━━━━━━━━━━━━━━

LEARN MORE FROM BRAINLY