Question

The number of points of intersection of the quadratic polynomial x^+4x+4 with the x-axis is

Answer 1

The point of intersection of the quadratic polynomial $x^{2}+4x+4$ is one which is (-2, 0)

• Let

               $y=x^{2}+4x+4$

• Finding points lying on this curve

              x:    -2      -1       0       1       2

              y:      0       1       4       9      16

• The points are (-2, 0), (-1, 1), (0, 4), (1, 9), (2, 16)

• Plotting these points on graph                      
• The curve is a parabola which intersects X-axis at (-2, 0)

Answer 2

The number of point of intersection of the given  quadratic polynomial with  the x- axis is 1.

Step-by-step explanation:

Given quadratic polynomial

$x^2+4x+4$

Suppose

$y=x^2+4x+4$

To find the zeroes of given quadratic polynomial we will substitute y=0

$x^2+4x+4=0$

$x^2+2\times x\times 2+(2)^2=0$

$(x+2)^2=0$

Using the formula

$(a+b)^2=a^2+b^2+2ab$

$x+2=0$

$x=-2$

Hence, the number of point of intersection of the given  quadratic polynomial with  the x- axis is 1.

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