Question

the number of points on x-axis which are at a distance of c units (c<3) from (2,3) is..​

Answer 1

Answer:

Here is your answer mate may this help you

Answer 2

Answer:

The Correct Answer would be all the numbers ranging between

$( - \infty - 2 )$, that is from minus infinity to 2

The number of all the points that lie on x-axis, that are strictly at a distance of c units, where c<3, from the point (2,3) range between

$(- \infty - 2)$

Step-by-step explanation:

Given: Distance, which is less than 3 units from a point (2,3).

To Find: Number of points which satifies the given condition.

Now, the points will be of form (x,0) as they lie on x-axis.

Distance = c < 3 units.

We know the distance formula between two points:

Distance (D) =

$\sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} }$

Applying this formula to the question, we have:

$\sqrt{ {(x - 2)}^{2} + {(0 - 3)}^{2} } = c$

Now, c < 3, hence, we have:

$= \sqrt{ {(x - 2)}^{2} + 9} < 3 \\ = {(x - 2)}^{2} + 9 < 9 \\ = {(x - 2)}^{2} < 0 \\ = (x - 2) < 0 \\ = x < 2$

Hence, the range would be

$( - \infty - 2)$