Math, asked by singhharman32212, 1 month ago

the number of points where the function f(x) = |x-3| is not differentiable is​

Answers

Answered by ansulsharma
0

Consider the given function.

Consider the given function.f(x)=∣x∣+∣x−1∣

Consider the given function.f(x)=∣x∣+∣x−1∣Since, it is an absolute function. So, it a continuous function.

Consider the given function.f(x)=∣x∣+∣x−1∣Since, it is an absolute function. So, it a continuous function.Let see the graph of the given function,

Consider the given function.f(x)=∣x∣+∣x−1∣Since, it is an absolute function. So, it a continuous function.Let see the graph of the given function,From the graph, it is clear that the function f(x) is not differentiable at x=0 and x=1.

Consider the given function.f(x)=∣x∣+∣x−1∣Since, it is an absolute function. So, it a continuous function.Let see the graph of the given function,From the graph, it is clear that the function f(x) is not differentiable at x=0 and x=1.Hence, points 0 and 1 where the function f(x) is non-differentiable.

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