The number of pollynomials having zeros as -2and3 is what?
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But we know that, if we multiply/divide any polynomial by any arbitary constant. Then, the zeroes of polynomial never change. Hence, the required number of polynomials are infinite i.e., more than 3.
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sum of zeroes(S) = -2+3 = 1
product of zeroes(P) = -2x3 = -6
x^2 + Sx + P
x^2 + 1x + (-6)
x^2 + x - 6
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