Question

the number of polynomial having zeros as 3and
-5 is​

Answer 1

Answer:

Infinite

Step-by-step explanation:

Polynomial having zeros 3 and - 5 is given by

$polynomial \: is \: given \: by \: a(x - 3)(x + 5) \\ this \: gives \: \\ a ({x}^{2} + 2x - 15)$

Here you can take any integer value for a

Ex:

${x}^{2} + 2x - 15 \\ 2 ({x}^{2} + 2x - 15 )\\ 3( {x }^{2} + 2x - 15)$

Answer 2

Given : polynomial having zeros as 3 and -5

To Find :  number of polynomial

Solution:

Polynomial having zeros  a and b can be represented by

k (x - a)(x - b)

where k is non zero  

Hence polynomial having zeros as 3 and -5

k (x - 3)(x - (-5))

=k (x - 3)(x + 5)

= k ( x²  + 2x  - 15)

Hence based on value of k we can get infinite polynomial having zeroes  as 3 and -5

Example

x²  + 2x  - 15

2x²  + 4x  - 30

3x²  + 6x  - 40   and so on

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