Question

the number of polynomials having 0s as -2 and 5

Answer 1

Answer:

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Answer 2

Zeroes of the polynomial are -2 and 5

So,

$\alpha = - 2 \: \: and \: \: \beta = 5$

Therefore,

Quadratic polynomial=

$= {x}^{2} - ( \alpha + \beta )x + \alpha \beta \\ = {x}^{2} - ( - 2 + 5)x + ( - 2) \times 5 \\ = {x}^{2} - 3x - 10$

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