Question

the number of polynomials having zeroes as -2 and 5 ​

Answer 1

$\huge \underline \mathfrak \red{ Solution}$

$\sf \implies \: let \: polynomial \: be \: {x}^{2} - ( \alpha + \beta )x + \alpha \beta$

$where \: zeros \: be \: \alpha \: and \: \beta$

$( \alpha + \beta ) = - 2$

$( \alpha \beta ) = 5$

$\sf \underline{now \: accoding \: to \: equation}$

${x}^{2} + 2x + 5$

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Answer 2

Step-by-step explanation:

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letpolynomialbex

2

−(α+β)x+αβ

( \alpha + \beta ) = - 2(α+β)=−2

( \alpha \beta ) = 5(αβ)=5

{x}^{2} + 2x + 5x

2 +2x+5

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