the number of possible line segments from 6 points such that no three points are collinear plz mark answer this i will mark u as brainliest give correct answer
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Question= the number of possible line segments from 6 points such that no three points are collinear
Solution:
If you meant to ask how many line segments can be drawn through any 2 points out of 6 points such that none are colinear, then you can simply arrange the points in a form of an Hexagon and draw lines between each points.
So, let’s name the points A, B, C, D, E & F.
Line segments that can be drawn would be
AB
AC
AD
AE
AF
BC
BD
BE
BF
CD
CE
CF
DE
DF
EF
i.e. 15 line segments.
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