The number of possible line segments from six non-collinear points is
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Given : six non-collinear points
To Find : number of possible line segment
Solution:
6 non-collinear points
selecting any 2 points out of 6 will form a different line segment
2 points out of 6 can be selected in ⁶C₂ ways
⁶C₂ = 6!/2!.4!
= 6 * 5 / 2 * 1
= 15
Hence number of possible line segments from six non-collinear points is 15
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