Question

the number of possible pairs of successive prime numbers such that each of them is greater than 40 and their sum is at most hundred is​

Answer 1

Answer:

Step-by-step explanation:

The successive prime numbers greater than 40 are 41,43,47,53,59,....

In given question sum is at most 100. should not exceed more than 100.

so pairs are,

(41,43) is 41+43=84, 84 is less than 100.

(43,47) is 43+47=90, 90 is less than 100.

(47,53) is 47+53=100,  we got atmost 100 as the answer.

so there are 3 possible pairs.

Ans: 3

Answer 2

Answer:

there are 3 possible pairs