Question

The number of prime factors in (3*5)^12 (2*7)^10 (10)^25

Answer 1

THE EQUATION CAN BE FACTORIZED AS  2^5*3^2*5^5*7^1.
THERE FORE TOTAL NUMBER OF PRIME FACTORS IS
(5+1)(5+1)(2+1)(1+1).
THEREFORE NUMBER OF PRIME FACTORS IS 216 

Answer 2

Answer: 94

Step-by-step explanation:

When it is reduced we get,

3^12*5^37*2^35*7^10

so, total no.of prime factors :12+37+35+10=94