The number of prime factors in (3*5)^12 (2*7)^10 (10)^25
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Answered by
1
THE EQUATION CAN BE FACTORIZED AS 2^5*3^2*5^5*7^1.
THERE FORE TOTAL NUMBER OF PRIME FACTORS IS
(5+1)(5+1)(2+1)(1+1).
THEREFORE NUMBER OF PRIME FACTORS IS 216
THERE FORE TOTAL NUMBER OF PRIME FACTORS IS
(5+1)(5+1)(2+1)(1+1).
THEREFORE NUMBER OF PRIME FACTORS IS 216
Answered by
2
Answer: 94
Step-by-step explanation:
When it is reduced we get,
3^12*5^37*2^35*7^10
so, total no.of prime factors :12+37+35+10=94
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