The number of protons in 4 moles of NaNO3 is mol
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Na = 11 protons
N = 7 protons
O = 8 protons
There are three oxygen atoms, so, there will be 24 protons
totally, 24 + 7 + 11 = 32 protons
in four moles of NaNO₃ = 4 x 6.022 x 32 x 10²³
770.816 x 10²³ protons, = 7.70816 x 10²⁵ protons
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Answer:
148 protons are there in NaNO3
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