Biology, asked by barbie1045, 1 year ago

The number of punctuation condons in a genetic code are
(a) 2 + 3 = 5
(b) 1 + 3 = 4
(c) 1 + 1 = 2
(d) 3

Answers

Answered by sumit9479
0

2+3=5 is the answer

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