Question

The number of quanta of radiation of frequency 4.98 x 1014 s- required to melt 100 g of ice are(latent of melting of ice is 33 joule per g)​

Answer 1

Answer:

Explanation:

As 1gm  of ice is needed to melt ice by requiring an energy of 33J.

As in the question, 100gm will hence require = 100*33 =3300J

We know that to find the total quanta of radiation we can use the formula of energy which is given by the equation.

E=hv

Where "E" is the Energy

"h" is the plank constant  which is 6.626*10^-36

and v is the frequency of radiation given in the data 4.98*10^14

Thus, the energy is E=(6.626*10^-36)x(4.98*10^14 )

                                 E=32.97*10^-20

                         

For 100joules of ice required radiation energy is 3300/(32.97*10^-20)

Which is approx 100quanta.

Thus, for 100 quanta is 10^22Joules

Answer 2

Answer:

The correct answer is 10^22

Explanation:

We can use the formula E=nhv

E=33×100 joule

h=6.6×10^-34

v=4.98×10^14

Putting in formula we get

n=10^22