Chemistry, asked by xyz3253, 10 months ago

The number of radial nodes and angular nodes for
d-orbital can be represented as
1) (n - 2) radial nodes + 1 angular node
= (n - 1) total nodes
2) (n-1) radial nodes + 1 angular node
= (n-1) total nodes
3) (n-3) radial nodes + 2 angular nodes
= (n-1-1) total nodes
4(n-3) radial nodes + 2 angular nodes
= (n - 1) total nodes​

Answers

Answered by vinaykumarranchi2018
8

Answer:

radial node= n-l-1

angular node = l

for d - orbital ,l=2

so, (4) n-2-1. +. 2= n-1

Explanation:

correct answer is (4).

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