The number of radial nodes of 3s and 2p orbitals are....
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For a given orbital with principal quantum number, n and azimuthal quantum number, l
Number of radial nodes = (n - l - 1)
Solution:
For 3s orbital: n = 3 and l = 0
Therefore, number of radial nodes = 3 - 0 - 1 = 2
For 2p orbital: n = 2 and l = 1
Therefore, number of radial nodes = 2 - 1 - 1 = 0
Number of radial nodes = (n - l - 1)
Solution:
For 3s orbital: n = 3 and l = 0
Therefore, number of radial nodes = 3 - 0 - 1 = 2
For 2p orbital: n = 2 and l = 1
Therefore, number of radial nodes = 2 - 1 - 1 = 0
Answered by
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Hi friend,
number of radial nodes for an orbital=n-l-1
for 3s n=3 l=0 so number of radial nodes will be 3-1=2
for 2p orbital n=2 and p=1 so radial nodes= 2-1-1=0.
number of radial nodes for an orbital=n-l-1
for 3s n=3 l=0 so number of radial nodes will be 3-1=2
for 2p orbital n=2 and p=1 so radial nodes= 2-1-1=0.
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