Math, asked by sarangjagtap350, 9 months ago

The number of real roots of quadratic equation (x-4)^2+(x-5)^2+(x-6)^2=0 is

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Answered by sargunk
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Step-by-step explanation:

The number of real roots of the quadratic equation (x-4)^(2)+ (x-5)^(2) + (x-6) ^(2) = 0 hope it will help you andPlease follow me

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