The number of real roots of the equation
is _____________?
Answers
Answered by
0
Heya...... .
so, x =1,2,3 at the same time
hence , no value of x exist so as to satisfy the given equation.
Hope it helps
Answered by
3
HIII .....
GOOD AFTERNOON:-)
HERE IS YOUR ANSWER:--------
(x-1)^2+(x-2)^2(x-3)^2=0
(x-1 x-2 x-3)^2
(x-6)^2=0
x^2 -12x +36=0
HOPE THIS HELPS YOU.....
HAVE A GREAT DAY AHEAD......✌
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