Question

the number of real roots of the equation (x- 1)² + (x -2 )²+ (x- 3)²=0 is

Answer 1

Answer:

нутаг озёрная олоод 2 Валаамда эдюулжэ та таалабад

Answer 2

$\huge\boxed{\underline{\underline{\green{\tt Solution}}}} </p><p>$

The given equation is

$(x- 1)² + (x -2 )²+ (x- 3)²=0$

$\implies \: {x}^{2} - 2x + 1 + {x}^{2} - 4x + 4 + {x}^{2} - 6x + 9 = 0$

$\implies \: 3 {x}^{2} - 12x + 14 = 0$

So the Discriminant

$= { \: ( - 12)}^{2} - 4 \times 3 \times 14$

$= 144 - 168$

$= - 24 \: < \: 0$

Hence there is no real root of the given Quadratic Equation

$</p><p></p><p>\displaystyle\textcolor{red}{Please \: Mark \: it \: Brainliest}$